## Why the Wii Sucks

### jeffxtreme:

Pretty funny.

EXPERT

Humor

youtube.com
13

Pretty funny.

Posted on Jan 22, 2009

Mathematics

metacafe.com
2,369

If anybody was wondering how to prove this method of multiplying two integers... here it is:

Pretend the numbers you want to multiply are x and y. To find there distance from 100, all you have to do is subtract the number from 100. So the table he wrote would look like this:

x 100 - x

y 100 - y

The difference between x and the difference of 100 and y, and the difference between y and the difference between 100 and x are the same. In other words,

x - (100 - y) = x + y - 100

y - (100 - x) = x + y - 100

Secondly, he multiplied the numbers on the right by each other: (100 - x)(100 - y). Because this product has to be less than 99 for the method to work correctly, the method is limited to numbers close to 100.

By writing (x + y - 100) in the thousands and hundreds place, the expression is in effect being multiplied by 100. The sum of this and (100 - x)(100 - y) is xy as shown below:

100(x + y - 100) + (100 - x)(100 - y) =

(100x + 100y - 10000) + (-100x - 100y + 10000) =

xy

By substituting 100 for c throughout the method, one could show numbers close to a 10, 1000, 10,000, etc. could be multiplied together with a slightly altered form of the method.

c(x + y - c) + (c - x)(c - y) =

(cx + cy - cc) + (-cx -cy + cc + xy) =

xy

Well, there you have it, this method proved in an extremely geeky fashion! :)

Posted on Sep 19, 2008

Humor

roxanne.org
7

Hilarious commentary on an "average" grad-student's day.

Posted on Sep 4, 2008

Humor

hilarious

Posted on Mar 11, 2008

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